The resultant force has of magnitude 9.66N and at an angle of 54.4° above the x axis.
The resultant force and is obtained by using the cosine.
Let the resultant force is be F
[tex]F = \sqrt{F_{1}^{2} + {F_{2}^{2} - 2*{F_{1} + {F_{2} *cos (90 +27)}[/tex]
[tex]F = \sqrt{6.3^{2} + 5^{2} - 2*6.3 + 5 *cos (117)}[/tex]
F = 9.66 unit
Using the sine rule to determine the direction:
9.66/sin 117 = 5/sin x
x = Sin⁻¹(5 * sin 117/9.66)
x = 27.4°
Therefore the direction is 27.4 + 27 = 54.4°
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