Question

Given the Coulomb's formula F= ke q1*q2/r^2 where ke= (9.0 * 10^9 N m^2/c^2)

F is the force between charges in Newton, Qr and Q2 are the respective two charges in Coulombs, and r is the distance in meters. Calculate the distance between two charges of 20μc and 18μC if the force between the two charges is 2.8x10^4 N

Answer 1

The distance between two charges is 1.075 cm.

Distance between the charges

The distance between the charges is calculated using Coulomb's law as shown below;

F = kq1q2/r²

Fr² = kq1q2

r² = kq1q2/F

r = √( kq1q2/F)

where;

• r is the distance between the charges
• F is the force of attraction

r = √( 9 x 10⁹ x 20 x 10⁻⁶ x 18 x 10⁻⁶/2.8 x 10⁴)

r = 0.01075 m

r = 1.075 cm

Thus, the distance between two charges is 1.075 cm.

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