Question

mole is equal to 6.022x1023 particles/atoms/molecules. how many chloride ions are presented when 1 mole of sodium chloride is mixed with 4 mole of magnesium chloride

Answer 1

When 1 mole of sodium chloride is mixed with 4 mole of magnesium chloride, the number of chloride ion present will be 5.4198 x $10^{24}$ molecules

Number of molecules in substances

1 mole of sodium chloride contains 1 mole of chloride ion according to the following equation:

NaCl ---> $Na^+$ + $Cl^-$

4 moles of magnesium chloride will contain moles of chloride ions according to the following equation:

$4MgCl_2 --- > 4Mg^{2+} + 8 Cl^-$

The total number of moles of chloride ions in solution:

1+8 = 9 moles.

1 mole of a substance = 6.022 x $10^{23}$

Thus, the total number of chloride ions present in the mixture = 9 x 6.022 x $10^{23}$

  = 5.4198 x $10^{24}$ molecules

More on number of molecules in substances can be found here: https://brainly.com/question/11907018

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