Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.)

The values of the functions are k(0) = 0, k(4) = 64, k(-4) = -192, k(1/2) = -3/4, k(a/2) = 2(a/2)^3 - 4(a/2)^2, k(x) = -2x^3 - 4x^2 and k(x^3) = 2x^9 - 4x^6
The function definition is given as:
k(x) = 2x^3 - 4x^2
To calculate the values of the function, we simply substitute the x value and then calculate the function value
Using the above highlight, we have the following computations
k(0) = 2(0)^3 - 4(0)^2
k(0) = 0
k(4) = 2(4)^3 - 4(4)^2
k(0) = 64
k(-4) = 2(-4)^3 - 4(-4)^2
k(-4) = -192
k(1/2) = 2(1/2)^3 - 4(1/2)^2
k(1/2) = -3/4
k(a/2) = 2(a/2)^3 - 4(a/2)^2
k(-x) = 2(-x)^3 - 4(-x)^2
k(-x) = -2x^3 - 4x^2
k(x^3) = 2(x^3)^3 - 4(x^3)^2
k(x^3) = 2x^9 - 4x^6
Hence, the values of the functions are k(0) = 0, k(4) = 64, k(-4) = -192, k(1/2) = -3/4, k(a/2) = 2(a/2)^3 - 4(a/2)^2, k(x) = -2x^3 - 4x^2 and k(x^3) = 2x^9 - 4x^6
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