Suppose that a system of seven equations with nine unknowns is in row echelon form, with no trivial (0=0) equations. how many leading variables are there?

Respuesta :

There are 7 leading elements in the system of seven equations with nine unknowns is in row echelon form, with no trivial (0=0) equations.

Row Echelon Form:

A matrix is in Row Echelon form if it has the following properties:

  • Any row consisting entirely of 0 occurs at the bottom of the matrix.
  • For each row that does not contain entirely zeros, the first non-zero entry is 1. It is called as leading 1.
  • For two successive non-zero rows, the leading 1 in the higher row is further left than the leading one in the lower row.

For reduced row echelon form, the leading 1 of every row contains 0 below and above its in that column.

Given,

Suppose that a system of seven equations with nine unknowns is in row echelon form, with no trivial (0=0) equations.

Here we need to find the number of leading variables.

Since we have

number of equations = 7

number of unknowns = 9

So, the row echelon for of the matrix is

=> 7 x 9

Based on this, we understand that, at most 7 leading variables.

Because in in each row there is at least one leading variable.

So, there are 7 leading variables.

To know more about Row Echelon Method here.

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