Question

A 0.25 kg ball moving north at 7.7 m/s experiences an impulse of 2.5 N-s acting due east. What is the magnitude
and direction of the ball's new velocity?

Answer 1

The new velocity of the ball is 17.7 m/s north-east.

What is velocity?

Velocity can be defined as the rate of change of displacement.

The S.I unit of velocity is m/s.

To calculate the magnitude and direction of the new velocity, we use the formula below.

Formula:

• m(v-u) = I.............. Equation 1

Where:

• m = mass of the ball
• v = New velocity of the ball
• u = Initial velocity of the ball
• I = Impulse

From the question,

Given:

• m = 0.25 kg
• u = 7.7 m/s
• I = 2.5 N-s

Substitute these values into equation 1

• 0.25(v-7.7) = 2.5
• v-7.7 = 10
• v = 10+7.7
• v = 17.7 m/s north-east

Hence, the new velocity of the ball is 17.7 m/s north-east.

Learn more about velocity here: https://brainly.com/question/4931057

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