The equation of the line that passes through the given point and is perpendicular to the given line is; 2y + 3x = -6.
It follows from the task content that the line required is perpendicular to the equation; y = (2/3)x + 4.
On this note, it follows that the slope of the required equation will be; -1/(2/3)
The slope of the line is; -3/2.
Hence, the equation of the required line is;
-3/2 = (y-(-6))/(x-2)
2y +12 = -3x +6
2y + 3x = -6.
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