Question

Find the distance and midpoint of AB if A = (10, -6) and B = (0, -2).
Distance of AB
Midpoint of AB :(
(Round to the nearest tenth.)
)

Answer 1

Answer:

distance = 10.8 units

midpoint: (5, -4)

Step-by-step explanation:

To find distance

$\sf d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$\sf d = \sqrt{(-2 -(-6))^2 + (0 -10)^2}$

$\sf d = \sqrt{(4)^2 + (-10)^2}$

$\sf d = \sqrt{16+ 100}$

$\sf d = \sqrt{116}\quad \approx \quad 10.8$

To find midpoint

$\sf (x_m, y_m) = \left(\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2}\right)$

$\sf (x_m, y_m) = \left(\dfrac{10+0}{2}, \dfrac{-6-2}{2}\right) = (5, -4)$