Question

What is the molality of a solution prepared by dissolving 84.7 g of kmno4 in 165 g of water?

Answer 1

The molality of the solution prepared by dissolving 84.7 g of $KMnO_{4}$ in 165 g of water is 3.25 moles per kg.

We know that,

Molality = Moles of solute/kgs of solvent

It is given that:-

Solute is $KMnO_{4}$

Amount of solute is 84.7g

Solvent is Water

Amount of solvent is 165g that is 0.165 kg

We know that:-

Number of moles of solute = Mass of substance/Mass of 1 mole

Here,

Mass of 1 mole of solute = 158g

Hence,

Number of moles of solute =  84.7/158 = 0.536 (approximately)

Hence,

Molality of the solution = 0.536/0.165 = 3.25 moles/kg (approximately)

To learn more about molality, here:-

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