Question

A rectangular lot whose perimeter is 300 ft is fenced along three sides. An expensive fencing along the​ lot's length cost $30 per foot. An inexpensive fencing along the two side widths costs only $6 per foot. The total cost of the fencing along the three sides comes to $3690. What are the​ lot's dimensions?

Answer 1

The given dimensions that we have in this question are 105 and 45

How to solve for the dimensions

We have 2(l + b ) = 300

l + b = 300/2

l + b = 150 ----- 1

The fencing would be

30l + (6b + 6b) = $3690

30l + 12b = 3690 ---- 2

We have to solve this through the use of simultaneous linear equation

The calculator that has been used to solve this is the simultaneous linear equation calculator.

This would give us the values of 105 and 45.

We have to conclude that the dimensions are 105 and 45

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