Respuesta :

The equation for the line passing through (-8,8) and parallel to the line whose equation is 5x-8y-7=0 is 8y - 5x - 104 = 0

How to write an equation for the line passing through (-8,8) and parallel to the line whose equation is 5x-8y-7=0?

The parallel equation is given as:

5x - 8y - 7 = 0

Add 7 to both sides of the equations

5x - 8y = 7

Rewrite the equation as:

8y = 5x - 7

Divide through the equation by 8

y = 5x/8 - 7/8

The slope of the above equation is 5/8

Parallel lines have equal slope

So, we have

m = 5/8

The equation is then calculated as:

y = m(x - x1) + y1

Where

(x1, y1) = (-8, 8)

So, we have:

y = 5/8(x + 8) + 8

Multiply through by 8

8y = 5(x + 8) + 64

Expand the bracket

8y = 5x + 104

This gives

8y - 5x - 104 = 0

Hence, the equation for the line passing through (-8,8) and parallel to the line whose equation is 5x-8y-7=0 is 8y - 5x - 104 = 0

Read more about linear equations at:

https://brainly.com/question/1884491

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