Answer:
B. [tex]s = \sqrt{ \frac{R - 3}{t} } [/tex]
Step-by-step explanation:
Solve for s in the equation: [tex]R = t {s}^{2} + 3[/tex]
Make s the subject of formula by collecting like terms.
[tex]t {s}^{2} = R - 3[/tex]
Divide both sides by the coefficient of s²
[tex] \frac{t {s}^{2} }{t} = \frac{R - 3}{t} [/tex]
[tex] {s}^{2} = \frac{R - 3}{t} [/tex]
Square root both sides because s is squared.
[tex] \sqrt{ {s}^{2} } = \sqrt{ \frac{R - 3}{t} } [/tex]
Therefore: [tex]s = \sqrt{ \frac{R - 3}{t} } [/tex] is the final answer.
Option A is almost correct but the square root is not for only [tex]R - 3[/tex] but for [tex]\frac{R - 3}{t} [/tex]
I hope this helps