Question

What is the midpoint of AC on the grid below?

Answer 1

Answer:

(- 1, 1 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

here (x₁, y₁ ) = A (2, 4 ) and (x₂, y₂ ) = C (- 4, - 2 ) , then

midpoint = ( $\frac{2-4}{2}$ , $\frac{4-2}{2}$ ) = ( $\frac{-2}{2}$ , $\frac{2}{2}$ ) = (- 1, 1 )