Question

A vehicle accelerates to 17.36 m/s after being stopped at a red light. The vehicle travels 24.99 m while accelerating from the intersection. How fast was its acceleration?

Answer 1

So, the vehicle's acceleration approximately 6.03 m/s².

Introduction

Hi ! I will help you to solve a problem about "acceleration in a straight line movement". When an object experiences an acceleration, the object will experience a change in the value of the velocity in a certain time interval. When experiencing a change in speed, of course, objects will move. This movement will be written as "s" (shift or displacement).

Formula Used

The formula that you can use to solve this question is:

$\boxed{\sf{\bold{(v_t)^2= (v_0)^2 + 2 \times a \times s}}}$

With the following condition :

• $\sf{v_t}$ = final velocity of an object (m/s)
• $\sf{v_0}$ = initial velocity of an object (m/s)
• a = acceleration that happen (m/s²)
• s = the shift or distance of the object (m)

Solution

We know that :

• $\sf{v_t}$ = final velocity of an object = 17.36 m/s
• $\sf{v_0}$ = initial velocity of an object = 0 m/s >> the vehicle initially stopped at the intersection.
• s = the shift or distance of the object = 24.99 m

What was asked ?

• a = acceleration that happen = ... m/s²

Step by step :

$\sf{(v_t)^2= (v_0)^2 + 2 \times a \times s}$

$\sf{(17.36)^2= (0)^2 + 2 \times a \times 24.99}$

$\sf{301.37 \approx 49.98 \times a}$

$\sf{a \approx \frac{301.37}{49.98}}$

$\boxed{\sf{a \approx 6.03 \: m/s^2}}$

Conclusion

So, the vehicle's acceleration approximately 6.03 m/s².

Learn More

Do you want to increase knowledge about how to calculate deceleration? Come learn at the following link : https://brainly.com/question/28008750