Given f(x) = 1/x+1 and g(x)--2x algebraically find the following

The values of the functions are f(g(4)) = 1/(2√2 + 1), g(g(2)) = 2 and g + f(2s^2) = 2s + 1/(2s^2 + 1)
The functions are given as:
f(x) = 1/x + 1
g(x) = √2x
Composite function f(g(4))
Start by calculating g(4).
So, we have:
g(4) = √2 * 4
Evaluate
g(4) = 2√2
So, we have:
f(g(4)) = f(2√2)
Evaluate
f(g(4)) = 1/(2√2 + 1)
Composite function g(g(2))
Start by calculating g(2).
So, we have:
g(2) = √2 * 2
Evaluate
g(2) = 2
So, we have:
g(g(2)) = g(2)
Evaluate
g(g(2)) = √2 * 2
g(g(2)) = 2
Composite function (g + f)(2s^2)
Start by calculating g(2s^2).
So, we have:
g(2s^2) = √2 * 2s^2
Evaluate
g(2s^2) = 2s
Next, we have:
f(2s^2) = 1/(2s^2 + 1)
So, we have:
g + f(2s^2) = 2s + 1/(2s^2 + 1)
Hence, the values of the functions are f(g(4)) = 1/(2√2 + 1), g(g(2)) = 2 and g + f(2s^2) = 2s + 1/(2s^2 + 1)
Read more about composite functions at:
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