The mass of the product is 25.5 g.
A reaction takes place between reactants and products in a reaction system. The reaction in this case could be written as;
4C3H6 + 6NO --> 4C3H3N + 6H2O + N2
Number of moles of C3H6 = 21.6 g/42 g/mol = 0.51 moles
Number of moles of NO = 21.6 g/30 g/mol = 0.72 moles
Given that 4 moles of C3H6 reacts with 6 moles of NO
0.51 moles of C3H6 reacts with 0.51 moles * 6 moles / 4 moles
= 0.77 moles
This implies that NO is the limiting reactant.
Hence;
6 moles of NO produces 4 moles of C3H3N
0.72 moles of NO produces 0.72 moles * 4 moles/6 moles
= 0.48 moles of C3H3N
Mass of C3H3N =0.480 mol ×53.06 g/mol= 25.5 g
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