The recoil velocity will be 5.42 m/s.
Newton 3rd law state that in every action, there will be equal and opposite reaction.
Given that a rifle bullet of mass 60.0 g leaves the muzzle of a rifle with a velocity of 2.8 x 10² m/s. If the rifle has a mass of 3.1 kg, with what velocity will it recoil ?
The parameter given are;
mu = Mv
Substitute all the parameters
0.06 × 2.8 × 10² = 3.1 v
16.8 = 3.1v
Make v the subject of formula
v = 16.8/3.1
v = 5.42 m/s
Therefore, the recoil velocity will be 5.42 m/s.
Learn more about Recoil Velocity here: https://brainly.com/question/15435914
#SPJ1