The mean value of the different species of plants in some gardens is 4.5 and the standard deviation of the different species of plants in some gardens is 2.06
How to determine the mean value?
The number of different species of plants in some gardens is given as:
1, 2, 3, 4, 4, 5, 5, 6, 7, 8
The mean value is calculated as:
Mean = Sum/Count
So, we have
Mean = (1 + 2 + 3 + 4 + 4 + 5 + 5 + 6 + 7 + 8)/10
Evaluate
Mean = 4.5
Hence, the mean value of the different species of plants in some gardens is 4.5
How to determine the standard deviation?
The number of different species of plants in some gardens is given as:
1, 2, 3, 4, 4, 5, 5, 6, 7, 8
The standard deviation is calculated as:
SD = √[∑(x - μ)²/n]
So, we have
SD = √[(1 - 4.5)^2 + (2- 4.5)^2 + (3- 4.5)^2 + (4- 4.5)^2 + (4- 4.5)^2 + (5- 4.5)^2 + (5- 4.5)^2 + (6- 4.5)^2 + (7- 4.5)^2 + (8- 4.5)^2 )/10]
Evaluate
SD = √4.25
This gives
SD = 2.06
Hence, the standard deviation of the different species of plants in some gardens is 2.06
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Complete question
The number of different species of plants in some gardens is recorded.
1, 2, 3, 4, 4, 5, 5, 6, 7, 8
a. What is the mean?
b. What is the standard deviation?
