Question

ASAP Help plsss!!!!
Solve for number 3 & 4 plssss!

Answer 1

Answer:

3. B

4. B

Step-by-step explanation:

3. 4$\sqrt{2}$

4 = $\sqrt{16}$

$\sqrt{16(2)}$

$\sqrt{32}$

4. 4x^2 + 4x - 6z - z + 3xy

4x^2 + 4x - 7z + 3xy

= 4x^2 + 3xy + 4x - 7z

Answer 2

It’s sqrt root of 32

When you do the sqrt root of 28 you get the same sqrt root of 4sqrt root of 2