A group 1 alkali metal bonded to iodide, such as NaI has the greatest electronegativity difference between the bonded atoms and is denoted as option A.
This is defined as the tendency of atoms to attract electrons thereby leading to a chemical reaction. On the other hand, electropositivity is the tendency of atoms to donate electrons in a reaction.
The Electronegativity value of iodine is 2.66 which is more than the remaining options provided such as nitrogen etc.
This is therefore the reason why group 1 alkali metal bonded to iodide was chosen as the most appropriate choice.
Read more about Electronegativity here https://brainly.com/question/2415812
#SPJ1
