Respuesta :

Answer:

[tex]1\frac78[/tex] meters tall

Step-by-step explanation:

Hello!

I'm assuming we're solving for the height of Shanika.

Let the height of Shanika be called "s".

Equation:  [tex]\frac32 = \frac45s[/tex]  

Solve for s

  • [tex]\frac32 = \frac45s[/tex]
  • [tex]$\frac{\frac32}{\frac45} = s[/tex]
  • [tex]\frac32 \div \frac45 = s[/tex]
  • [tex]\frac{3*5}{2*4} = s[/tex]
  • [tex]\frac{15}{8} = s[/tex]
  • [tex]1 \frac78 = s[/tex]

Shanika is [tex]1\frac78[/tex] meters tall.

ACCESS MORE