Answer:
[tex]R=9[/tex]
[tex]s=3.0972[/tex]
Step-by-step explanation:
Range ([tex]R[/tex]) is the highest value minus the lowest value.
The highest value in the data is 10, and the lowest value in the data is 1.
[tex]R=10-1=9[/tex]
To find the standard deviation of a sample ([tex]s[/tex]) without a calculator, use the sample variance formula for samples: [tex]s^{2} =\frac{n(\Sigma{X^2})-(\Sigma{X})^2}{n(n-1)}[/tex], where [tex]{X}[/tex] represents each individual value and [tex]n[/tex] represents the sample size.
1. Find the sum of the values.
[tex]\Sigma{X}=1+7+2+1+4+7+3+5+10+9+1+4+3+5+8+1+1+8+5+5+6+10+10+7=123[/tex]
2. Square each value and find the sum.
[tex]\Sigma{X}^{2}=1^{2}+7^{2}+2^{2}+1^{2}+4^{2}+7^{2}+3^{2}+5^{2}+10^{2}+9^{2}+1^{2}+4^{2}+3^{2}+5^{2}+8^{2}+1^{2}+1^{2}+8^{2}+5^{2}+5^{2}+6^{2}+10^{2}+10^{2}+7^{2}=851[/tex]
3. Substitute it into the sample variance formula.
[tex]s^{2} =\frac{n(\Sigma{X^2})-(\Sigma{X})^2}{n(n-1)}=\frac{24(851)-(123)^2}{24(24-1)}=\frac{20424-15129}{24(23)}=\frac{5295}{552}=\frac{1765}{184}[/tex]
4. Take the square root of the sample variance to get the sample standard deviation.
[tex]\sqrt{s^2}=\sqrt{\frac{1765}{184} }=3.097158586[/tex]
5. Round the sample standard deviation to four decimal places.
[tex]s=3.0972[/tex]