Question

You are asked to draw a colored marble out of a box. The are 5 red marbles, 11 blue
marbles, and 4 green marbles in the box. What is the probability of drawing a red marble
and then a green marble without replacing the first marble? Round to 3 decimal places.

Answer 1

As per the question-mentioned condition, the probability of drawing a red marble and then a green marble without replacing the first marble, rounded to 3 decimal places will be 0.053.

As mentioned in the question statement, the box contains 5 red marbles, 11 blue marbles, and 4 green marbles and we have asked to draw two marbles out of the box, one after another.

Here, total number of marbles in the box initially before starting to draw was $(5+11+4)=20$ marbles.

Therefore, probability of drawing a red marble in the first draw will be $\frac{5}{20}=\frac{1}{4}=0.25$.

Now, after the first draw, since it is conditioned in the question-statement that the first marble will not be replaced, then the number of remaining marbles in the box will be $[(5-1)+11+4)=19$ marbles, 4 red, 11 blue and 4 green.

Now, the probability of drawing out a green marble will be $\frac{4}{19}=0.21052=0.211$.

Hence, the probability of drawing a red marble and then, a green marble without replacing the first one will be $(0.25*0.211)=0.05275=0.053$.

• Probability: In mathematics, probability is the extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.

To learn more about probability, click on the link below,

https://brainly.com/question/21324796

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