Question

Determining percent error: A student was supposed to measure 200.0 milliliters of water and
obtained 196.0 milliliters instead. Her partner was supposed to measure 50.0 mL of water and obtained
48.0 mL instead. Determine who had the largest percent error in correct sig figs. The equation is shown.
Formula for % error= (measured -true)/ true x 100

Answer 1

The student's partner had the larger percent error.

Percent error

The percent error in a measurement is given by:

Percent error = error/true measurement x 100

Whereas: error = |true measurement - actual measurement|

For the student:

Error = 200.0 - 196.0 = 4.0 millimeters.

For her partner:

Error = 50.0 - 48.0 = 2.0 mL

Percent error for the student = 4.0/200 x 100

                                      = 2.0 %

Percent error for her partner = 2.0/50.0 x 100

                                        = 4.0 %

Thus, the student's partner had the largest percent error. Her partner's error actually doubles her own,

More on percent errors can be found here: https://brainly.com/question/3670306

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