Answer:
[tex]n=\frac{5}{33}[/tex]
Step-by-step explanation:
Question 1:
The decimal number n has two repeating digits (1 and 5). 0.151515... repeats forever.
Question 2:
In order to find the fractional equivalent of n, we can multiply n by 10 to the power of the number of repeating digits. We identified that quantity to be 2, in the previous question, so we can conclude that we must multiply n by [tex]10^2[/tex], which is 100
Question 3:
We can set up an equation that sets [tex]10^2n[/tex] equal to our decimal times [tex]10^2[/tex]:
[tex]10^2*n=10^2*0.151515...\\100n=100*0.151515...\\100n=15.1515...[/tex]
Note that when you multiply a number by 100, you can just move the decimal point two places to the right
Question 4:
Now, we can set up a system of equations using the one we found in question 4 and the one given to us at the start of the problem:
[tex]100n=15.1515...\\n=0.1515...[/tex]
Question 5:
We can subtract the bottom equation from the top by subtracting the components on the left and subtracting the components on the right. After we do this, we can just solve for n:
[tex]100n-n=15.1515...-0.1515...\\99n=15\\n=\frac{15}{99}=\frac{5}{33}[/tex]
Note that, when you subtract the two decimal numbers, the repeating parts go away since they are both technically the same quantity (in that they are the same numbers and the repeat infinite times)
That being said, our final fraction is 5/33 after simplication