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Jaya is the middle of three siblings whose ages are consecutive even integers. If the sum of their ages is 8484, find Jaya's age

Jaya is the middle of three siblings whose ages are consecutive even integers If the sum of their ages is 8484 find Jayas age class=

Respuesta :

Jaya's age is 2828, which is the middle age of the three siblings

What is an integer?

An integer is an whole number without decimal or fractional part, which means 1,2,3 are integers since they not in decimals or fractions.

Note the word consecutive means the ages of the three siblings are one after the other.

Let us assume the youngest sibling's age is X

Next sibling's age is X+1

The last sibling's age is X+2

sum of their ages=X+X+1+X+2

sum of their ages=3X+3

sum of their ages=8484

8484=3X+3

8484-3=3X

X=(8484-3)/3

X=age of the youngest sibling=2827

the age of the next sibling=2828

age of the last sibling=2829

The middle age is 2828(i.e2827+2828+2829)/3))

Find out more about mean on:https://brainly.com/question/20118982

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Answer:

Jaya's age is 28.

Step-by-step explanation:

26+28+30=84

Hope this helps!

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