Question

For the given midpoint of (8, -2) and endpoint B(3,5) find A on AB.

Answer 1

Answer:

A (-2, 12)

Step-by-step explanation:

plug the midpoint into the midpoint formula setting each equation equal to its respective value.

$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})\\x:\frac{8+x_2}{2}=3\\8+x_2=6\\x_2=-2\\\\y:\frac{-2+y_2}{2}=5\\-2+y_2=10\\y_2=12\\\\A(-2,12)$

Answer 2

Step-by-step explanation:

as we know the midpoint coordinates are

xm = (xa + xb)/2

ym = (ya + yb)/2

m being the midpoint, a and b being the endpoints.

so, we have here

8 = (xa + 3)/2

16 = xa + 3

xa = 13

-2 = (ya + 5)/2

-4 = ya + 5

ya = -9

therefore,

A = (13, -9)