The position of bus relative to the light after 20 seconds is 1,645 m. and the final velocity of the bus is 57.5 m/s.
The final velocity of an object is the last velocity of the object before coming to rest.
v = u + at
where;
v = 12.5 + (2.5 x 18)
v = 57.5 m/s
s = vt + 0.5at²
s = 57.5(20) + 0.5(2.5)(20²)
s = 1,650
Position of bus relative to the light = 1650 m - 5m = 1,645 m.
Thus, the position of bus relative to the light after 20 seconds is 1,645 m. and the final velocity of the bus is 57.5 m/s.
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