bus is 5 meters behind a traffic light and traveling at 12.5 m/s when it starts accelerating at 2.50 m/s 2 . If it accelerates for 18.0 seconds, what is the final velocity? Where will the bus be, relative to the light, after 20.0 seconds?

Respuesta :

The position of bus relative to the light after 20 seconds is 1,645 m. and the final velocity of the bus is 57.5 m/s.

What is final velocity?

The final velocity of an object is the last velocity of the object before coming to rest.

v = u + at

where;

  • v is the final velocity
  • u is the initial velocity
  • a is acceleration
  • t is time

v = 12.5 + (2.5 x 18)

v = 57.5 m/s

Distance traveled by the bus after 20 seconds

s = vt + 0.5at²

s = 57.5(20) +  0.5(2.5)(20²)

s = 1,650

Position of bus relative to the light = 1650 m - 5m = 1,645 m.

Thus, the position of bus relative to the light after 20 seconds is 1,645 m. and the final velocity of the bus is 57.5 m/s.

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