The acme company manufactures widgets, the distribution of widget weights is bell-shaped. The widget weights have a mean of 37 ounces and a standard deviation of 3 ounces.

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26-08-2022
Mathematics

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The acme company manufactures widgets, the distribution of widget weights is bell-shaped. The widget weights have a mean of 37 ounces and a standard deviation of 3 ounces.

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yogeshkumar49685 yogeshkumar49685 · Answer 1 · 2022-08-31T15:05:14+02:00

If the mean of the weights is 37 ounces and the standard deviation is 3 ounces then 34.13% of the percentage lies between 37 ounces and 40 ounces.

Given that the mean of the weights is 37 ounces and the standard deviation is 3 ounces.

We are required to find out the percentage of weights that lie between 37 and 40 ounces.

Because the distribution is bell shaped so it is a normal distribution and because we donot know the sample size so we will use z statistics.

Z=(X-μ)/σ

Z=(40-37)/3

Z=3/3

Z=1

p value of Z=1 is 0.3413 so the percentage will be 34.13%.

Hence if the mean of the weights is 37 ounces and the standard deviation is 3 ounces then 34.13% of the percentage lies between 37 ounces and 40 ounces.

Learn more about z score at https://brainly.com/question/25638875

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Question is incomplete. It should includes the following line.

Calculate the percentage of weights that lie between 37 ounces and 40 ounces.