Question

At the end of the summer, I decided to drain the one, 500-gallon swimming pool. I noticed that drains faster when there is more water in the pool. That was interesting to me, so I decided to measure the rate at which it rained. I found that 3% with draining out of school every minute. Use a table, a graph, and an equation to create a mathematical model of a gallons of water in the pool at t minutes.

Answer 1

The equation to represent the amount that will remain after t minutes will be 500 - 0.03t.

How to calculate the equation?

From the information, the water to be drained is about 500-gallon from the swimming pool.

And also, the person will drain 3% out every minute.

Therefore, the equation to represent the amount that will remain after t minutes will be:

= 500 - (3% × t)

= 500 - 0.03t

Therefore, the equation to represent the amount that will remain after t minutes will be 500 - 0.03t.

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Answer 2

Answer:

  equation: w(t) = 500×0.97^t

Step-by-step explanation:

You want a table, graph, and equation modeling the remaining water in a 500-gallon pool after t minutes when it drains at the rate of 3% per minute.

Equation

At the end of each minute, the remaining water (w) in the pool is 1 -3% = 0.97 of the amount at the beginning of the minute. The number of minutes (t) tells how many times 0.97 is a multiplier of the original quantity. Starting with 500 gallons, the number of gallons remaining is ...

  w(t) = 500·0.97^t . . . . equation

Table and Graph

A table of values and a graph are attached. We note that it takes about 3.4 hours for there to be 1 gallon remaining in the pool.