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What is the height of an isosceles trapezoid if the lengths of its bases are 5 m
and 11 m and the length of a leg is 4 m?

Respuesta :

The height of the isosceles trapezoid is 2.65 meters

How to determine the height of the isosceles triangle?

The given parameters are:

Base 1 = 5 meters

Base 2 = 11 meters

Length of a leg (l) = 4 meters

The height (h) of the isosceles triangle is calculated using the following Pythagoras theorem

h^2 = l^2 - x^2

Where

x = (base 2 - base 1)/2

So, we have

x = (11 -5)/2

This gives

x = 3

Recall that

h^2 = l^2 - x^2

Substitute the known values in the above equation

h^2 = 4^2 - 3^2

Evaluate the exponents

h^2 = 7

Take the square roots

x = 2.65

Hence, the height of the isosceles trapezoid is 2.65 meters


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