Point D is located on MN at (2,43). What ratio relates MD to DN?

The ratio of MD to DN is equal to 2.
In accordance with the image set aside, the locations of the points M and N are M(x, y) = (- 6, - 4) and N(x, y) = (6, 4), respectively. Now we determine the vectors associated to line segments MD and DN by vector sum:
MD = D(x, y) - M(x, y)
MD = (2, 4 / 3) - (- 6, - 4)
MD = (8, 16 / 3)
DN = N(x, y) - D(x, y)
DN = (6, 4) - (2, 4 / 3)
DN = (4, 8 / 3)
Lastly, we find the length of each line segment by Pythagorean theorem:
MD = √[8² + (16 / 3)²]
MD = (8 / 3)√13
DN = √[4² + (8 / 3)²]
DN = (4 / 3)√13
And the ratio of MD to DN is:
MD / DN = [(8 / 3)√13] / [(4 / 3)√13]
MD / DN = 2
The ratio of MD to DN is equal to 2.
The statement presents typing mistakes, we kindly present the correct form below:
Point D is located on line segment MN at (2, 4 / 3). What ratio relates MD to DN?
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