Question

GIVE BRAINLIEST!!!!!

A new Youth Activity Center is being built in Del Rio. The perimeter of the rectangular playing field is 352 yards. The length of the field is 4 yards less than double the width. What are the dimensions of the playing field? ​

Answer 1

Answer: length = 116, width = 60. Or 116x60 yards

Step-by-step explanation:

The length of the field is 4 yards less than double the width. First, let's put this in mathematical terms.

Suppose L = length and W = width, we know that "The length of the field is 4 yards less than double the width". This can be expressed as L = 2W-4.

Now we know perimeter is length + length + width + width. In terms of L and W, this would be 2L + 2W. We can simplify this to 2(L+W).

Since we know L = 2W-4, we can plug it into the equation of 2(L+W) to get 2(2w-4+w) = 352.

We can then use some basic algebra to solve.

2(3w-4) = 352

3w-4 = 176

3w = 180, w = 60.

Now since L = 2W-4, we know that L = 60 x 2 - 4 = 116.

We can check our work by adding 116 + 116 + 60 + 60 to see if it equals 352. It does.

So length = 116, width = 60