Question

Suppose that the function g is defined, for all real numbers, as follows

Answer 1

The value of the asked function are g(-4)=1/3 ,g(2)=4 and g(5)=10/3 respectively.

g(x)=$\left \{ {{1/3 x^{2} -5 if x\neq 2} \atop {4 if x=2}} \right.$

Here we have to find g(-4)

Here in the given equation it is written that if $x\neq 2$ so we have to use 1/3 $x^{2}$-5

so putting x=-4 in the given function

=1/3*(-4)(-4)-5

=1/3

so g(-4)=$\frac{1}{3}$

Now putting x=2 so it is given in the function that if x=2 then the value is 4.

g(2)= 4

Here in the given equation it is written that if $x\neq 2$ so we have to use 1/3 $x^{2}$-5  so again using this function and putting x=5 as we have to find g(5)

so putting x=5 in the given function

=1/3*(5)(5)-5

=$\frac{10}{3}$

so g(5)=$\frac{10}{3}$

so we have obtained the required values.

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