On a town map, each unit of the coordinate plane represents 1 mile. Three branches of a
bank are located at A(-3, 1) B(2, 3), and C (4, -1) . A bank employee drives from
Branch A to Branch B and then drives halfway to Branch C before getting stuck in
traffic.
What is the minimum total distance the employee may have driven before getting stuck
in traffic? Round to the nearest tenth of a mile.

Respuesta :

Answer:

[tex]\sqrt{29} +\sqrt{5}[/tex] = 7.6 miles

Step-by-step explanation:

[tex]\sqrt{(2+3^2)+(3-2)^2} +(\frac{\sqrt{(4-2)^2+(-1-3)^2} }{2} )[/tex]

[tex]\sqrt{29} +\frac{2\sqrt{5} }{2}[/tex]

[tex]\sqrt{29} + \sqrt{5}[/tex]

equals 7.6 (rounded to nearest tenth)

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