As a result of doubled resistance, current will be halved.
As we know, Ohm's law inversely relates current and resistance to each other. The equation is as follows -
V = I*R, where V is voltage, I is current and R is resistance.
As the question mentions no change in any other parameter, let's assume I₁ and I₂ be initial and final current and R₁ and R₂ initial and final resistance.
So, R₂ will be 2R₁ as it is doubled.
Now, equating the values and finding out the value of final current.
I₁R₁ = I₂R₂
Keep the value of R₂
I₁R₁ = I₂2R₁
Cancelling R₁ as it is common on both sides of equation.
So, we get - I₁ = 2I₂
I₂ = I₁/2
Thus, as can be seen above, final current will be half of initial current.
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