Yes, these two objects have different masses.
To calculate the precision of mass we are using the formula,
Precision(P) = [tex]\frac{m_1}{m_1+\triangle m}[/tex]
Or,[tex]\triangle[/tex]m=[tex]\frac{m_1}{P}[/tex]-m₁
For the first case we are given,
m₁= The recorded value of mass
= 128.01 g
P= Precision of the mass
=0.005g
So, according to the formula, [tex]\triangle[/tex]m will be,
[tex]\triangle[/tex]m= [tex]\frac{128.01}{0.005}[/tex]-128.01
Or,[tex]\triangle[/tex]m=25,473.99 g
Or,[tex]\triangle[/tex]m=25.47 Kg
For the first case [tex]\triangle[/tex]m is 25.47 Kg..
For the second case we are given,
m₁= The recorded value of mass
= 0.13 Kg
P= Precision of the mass
=0.005 Kg
So, according to the formula, [tex]\triangle[/tex]m will be,
[tex]\triangle[/tex]m= [tex]\frac{0.13}{0.005}[/tex]-0.13
Or,[tex]\triangle[/tex]m= 25.87 kg
For the second case [tex]\triangle[/tex]m is 25.87 Kg.
For the two cases [tex]\triangle[/tex]m has different values, 25.47 Kg≠25.87 Kg.
Therefore we can conclude that, these two objects have different masses.
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