Question

To produce 1.18 kg of solid potassium from molten KCl. How many hours must 0.743 amps be passed through the KCl?

Answer 1

The 0.0080 hour have passed through the KCl.

Calculation of  time:

given,

m = 1.18 kg

current I = 0.743 Amp/s

M.wt of potassium = 39.10 g

Moltan KCl

KCl  → $K^{+}$ +$Cl^{-}$

$K^{+} +1e^{-}$→ K

n = 1 mole

m = M.wt x I x t/n x F

t = m x n x F/ M.wt x I

= 1.18 kg x 1 mole x 96000/ 39.10g x 0.743

= 29.0513/3600

= 0.0080 hour

Hence, the 0.0080 hour have passed through the KCl.

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