Quantity of water form will be 36 gram
We need a stoichiometric equation for water synthesis:
H2(g) + 1/2O2(g) → H2O(l)
Clearly, dihydrogen must be present in a 2:1 molar ratio with respect to dioxygen.
Moles of dihydrogen = 4.8/2 = 2.4 moles
Moles of dioxygen = 38.4/32 = 1.2 moles
Given these molar quantities (they are approx. 2:1) the gases are present in stoichiometric proportion. 2mol water are going to be produced.
2 mol x 18g/mol = 36 gram
So, quantity of water form will be 36 gram
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