The relationship between 3x+4y=1 and 6x+8y=2 is that they are parallel lines.
Any linear equation has the form of y=mx+b
m is the slope of the equation
b is the y-intercept
The easiest way to see the relationship between the two lines is to transform them both into slope-intercept form, which is y=mx+b.
Equation 1 can be rewritten as
3x+4y=1
4y=1-3x
y= [tex]\frac{1-3x}{4}[/tex]
Equation 2 can be rewritten as:
6x+8y=2
8y=2-6x
y = [tex]\frac{2-6x}{8}[/tex]
Y= [tex]\frac{1-3x}{4}[/tex]
In this form, we can easily identify that both lines have a slope of [tex]-\frac{3}{4}[/tex], but that they have different y-intercepts. Lines will equal slopes but different y-intercepts are parallel.
Therefore, the lines are parallel.
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