The total number of protons which will be emitted by the transmitter will be 0.236 x [tex]10^{31}[/tex]
Power of transmitter P = 160kW
P = 160 x [tex]10^{3}[/tex] W
Frequency of the transmitter ν = 102.3 MHz
ν = 102.3 x [tex]10^{6}[/tex] Hz
Number of photons emitted per second
[tex]N=\frac{p}{hv}[/tex]
[tex]N=\frac{160 X 10^{3} }{(6.6 X 10^{-34} )(102.3 X 10^{6} )}[/tex]
N=0.236 x [tex]10^{31}[/tex] protons emitted per second
So, the total number of protons which will be emitted by the transmitter will be 0.236 x [tex]10^{31}[/tex]
To learn more about the Proton emission
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