0.34 ll of hno3hno3 is titrated to equivalence using 0.14 ll of 0.1 mnaohmnaoh. What is the concentration of the HNO3?

Respuesta :

When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M

The reaction of neutralization of HNO₃ with NaOH is

HNO₃ + NaOH → H₂O + NaNo₃

When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -

With the mole and volumes, we can find molarity as follows:

           Moles of NaOH = moles HNO₃

           ⁼ 0.14 L X (0.1 mol NaOH/L) = 0.014 mole NaOH

           =0.014 mol HNO₃

Molarity:

Moles of HNO₃/ volume of HNO₃ = 0.014/0.34

                                                        = 0.041

What is molarity ?

  • Measures of the concentration of a chemical solution include molarity and molality. The main distinction between the two is between volume and mass.
  • While molarity is concerned with the moles of a solute in respect to the volume of a solution, molality discusses the moles of a solute in relation to the mass of a solvent.
  • The quantity of a material in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.
  • Molarity is measured in units of M or mol/L. One molar is used to describe a 1 M solution.
  • M = moles solute / liters solution
  • is the molarity formula.

To view more about the molarity concept, refer to:

https://brainly.com/question/28165559

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