The light bulb remains lighted longer when the capacitor is charging when it is compared to the capacitor which is discharging. As the voltage between the two plates is continuously decreased while discharging until it hits zero.
The amount of current flowing inside the lightbulb determines the brightness of the bulb. The brightness of the light grows along with the amount of current flowing through the lightbulb. The internal resistance of the light bulb is constant, [tex]I= \frac{V}{R}[/tex] , and as the voltage drops, the current drops as well, which results in a reduction in the brightness of the light output.
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