The angle is 75.52 degrees
If there is a vector with the form a i + b j, the cosine of the angle between the given vector and the positive direction of the x - axis is calculated as:
cos θ = [tex]a/\sqrt{a^{2}+b^{2} }[/tex]
So, given the vector i+[tex]\sqrt{15 j[/tex], the cosine of the angle between the vector and the x-axis is:
cos θ = 0.25
Therefore, the angle θ between the given vector and the positive direction of the x-axis is:
θ = cos-1(0.25) = 75.52
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