A stone falls from the top of a building and hits the ground at a speed of 32 m/s. The air resistance force on the stone is very small and may be neglected, the time for the fall of the stone would be 1.806 seconds
What are the three equations of motion?
There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
height of the building (S) = 32 meters
initial velocity(u) = 0 m/s
acceleration(a) = 9.81 m/s²
By second equation of motion given by newton
S = ut + 1/2at²
S = 32 m ,u= 0 m/s , a= 9.81 m/s² and t =? seconds
32 = 0 + 9.81t²
t² = 32/9.81
t = 1.806 seconds
Thus, The time for the fall of the stone would be 1.806 seconds
Learn more about equations of motion from here
brainly.com/question/5955789
#SPJ1
