Solve for t: 15 = -6t - (3/5) x (3 - 2t).

I know you can multiply both sides by 5 to get rid of the fraction, but do I need to multiply (3 - 2t) by 5 or not?

Please help thank you (just respond yes or no)!

Solve for t 15 6t 35 x 3 2t I know you can multiply both sides by 5 to get rid of the fraction but do I need to multiply 3 2t by 5 or not Please help thank you class=

Respuesta :

Answer:

-7/2 = t

Step-by-step explanation:

15 = -6t - (3/5) * (3 - 2t)

Solve for t

Multiply each side by 5 to clear the fractions

5 * 15 =  5*-6t - 5* (3/5) * (3 - 2t)

The 5  cancels the 5 in the denominator of the fraction 3/5 leaving only the 3.

75 = -30t - 3 ( 3-2t)

Distribute

75 = -30t -9 + 6t

Combine like terms

75 = -24t -9

Add 9 to each side.

75 +9 = -24t-9+9

84 = -24t

Divide each side by -24

84/-24 = -24t/-24

-7/2 = t

Hi1315

Answer:

[tex] \pink{t = - 3.5}[/tex]

Step-by-step explanation:

[tex] \text{solve \: the \: brackets} \\ 15 = - 6t - \frac{3}{5} (3 - 2t) \\15 = - 6t - \frac{9}{5} + \frac{6t}{5} \\ \text{combine \: like \: terms } \\ 15 = \frac{ - 6t \times 5}{1 \times 5} - \frac{9}{5} + \frac{6t}{5} \\ 15 = \frac{ - 30t}{5} - \frac{9}{5} + \frac{6t}{5} \\15 = \frac{ - 24t}{5} - \frac{9}{5} \\ 15 = \frac{ - 24t - 9}{5} \\ \text{use \: cross \: multiplication} \\ 15 \times 5 = - 24t - 9 \\ 75 = - 24t - 9 \\ 75 + 9 = - 24t \\ 84 = - 24t \\ \text{ \: divide \: both \: sides \: by \: } - 24 \\ - 3.5 = t[/tex]

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