Question

pythagorean theorem

thanks

Answer 1

$3^2 + b^2 = 11^2 \\ \\ 9+b^2 = 121 \\ \\ b=\boxed{\sqrt{112}}$

Answer 2

Answer:

b = √112

Step-by-step explanation:

a^2 + b^2 = c^2

3^2 + b^2 = 11^2

b^2 = c^2 − a^2

b^2 = 11^2 − 3^2

√b^2 = √11^2 − 3^2

b =√11^2 − 3^2

b = √11^2 − 3^2

b = √121 − 9

b = √112