A rational function f with a slant asymptote y=x+4, a vertical asymptote at x=5, and one of the zeros at x=2 is f(x) = x^2 + 2x -8/x-5
For the vertical asymptote, the denominator must contain (x−5) and for zeros, the numerator must contain (x−2)
So far f(x)= x−2/x-5
Hence, for the slant asymptote, the quotient of the numerator divided by the denominator must be (x+4)
Therefore:
f(x)= (x+4)(x−2)/x−5
So f(x) = x^2 + 2x -8/x-5
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