1. a 0. 338-g sample of antimony was completely reacted with 0. 295 g of chlorine gas to form antimony chloride. determine the empirical formula of the antimony chloride

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04-08-2022
Physics

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1. a 0. 338-g sample of antimony was completely reacted with 0. 295 g of chlorine gas to form antimony chloride. determine the empirical formula of the antimony chloride

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Tutorconsortium353 Tutorconsortium353 · Answer 1 · 2022-08-09T16:46:38+02:00

The empirical formula of the antimony chloride is [tex]SbCl_{3}[/tex].

How to determine the empirical formula?

Chemical formulas for compounds that simply specify the proportions of the elements they contain rather than the exact number or arrangement of atoms are known as empirical formulas. The element in the compound with the lowest whole number ratio would be this one.

Data obtained from the question

Antimony (Sb) = 0.338 g

Chlorine (Cl) = 0.295 g

Divide by their molar mass.

Sb = 0.338 / 122 = 0.0028

Cl = 0.295 / 35.5 = 0.0083

Divide by the smallest.

Sb = 0.0028 / 0.0028 = 1

Cl = 0.0083 / 0.0028 = 3

Thus, the empirical formula of the compound is SbCl₃.

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