Question

If the water potential of a cell is -800kpa and solute potential of the same cell is 600 kpa then the water potential of that cell at equilibrium is?

Answer 1

The water potential of that cell at equilibrium is -200kpa.

Solution:

given that

Water potential $\psi = -800kpa$

solute potential $\psi _s = 600kpa$

we need to find water potential at equilibrium $\psi _ w = ?$

We know that water potential = $\psi = -\psi_s + \psi_w$

-800 = -600 + $\psi _w$

$\psi _w$ = -200kpa

What is Water Potential?

• The potential energy of water per unit volume in comparison to pure water under reference conditions is known as water potential. The tendency of water to migrate from one place to another due to osmosis, gravity, mechanical pressure, and matrix effects like capillary action is measured by water potential (which is caused by surface tension).
• Understanding and computing water movement inside plants, animals, and soil have proven to be made easier by the concept of water potential. Greek letter is frequently used to symbolize water potential, which is normally stated in terms of potential energy per unit volume.
• Water potential combines a number of various water movement-related potential forces that may work in parallel or in opposition to one another. Numerous possible elements may be active at once in complicated biological systems.

To learn more about water potential with the given link

https://brainly.com/question/17029221

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